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VK3ABK > TECH 18.10.06 08:34l 38 Lines 1315 Bytes #999 (0) @ WW
BID : 41576_VK3HEG
Read: GUEST OE5EWL DL8FBH DL1LCA DH0GHU
Subj: Re: Congrats. Phys. DK2ZA.
Path: DB0FHN<DB0MRW<DK0WUE<SP7MGD<VK7AX<VK3HEG
Sent: 061018/0236Z @:VK3HEG.#WEV.VIC.AUS.OC #:41576 [Ballarat] $:41576_VK3HEG
From: VK3ABK@VK3HEG.#WEV.VIC.AUS.OC
To : TECH@WW
Hello again,
Helmut, DK2ZA, Sent this network that asks for the resistance A - B.
---------------------------------------
| |
A |--------| | |--------| |--------| | B
o---------| 10 Ohm |---------| 10 Ohm |---------| 10 Ohm |---------o
| |--------| |--------| | |--------|
| |
---------------------------------------
Many people find it difficult to determine the resistance between A and B.
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Comment...But I see this network in a different way....
A B
³ 10 ³
ÃÄÄÄÄÄÄ/\/\/\/\/\ÄÄÄÄÄÄÄ´
³ 10 ³
ÃÄÄÄÄÄÄ/\/\/\/\/\ÄÄÄÄÄÄÄ´
³ 10 ³
ÀÄÄÄÄÄÄ/\/\/\/\/\ÄÄÄÄÄÄÄÙ
I thought I would use my old diagram for Helmut's previous question. I don't
like to see it wasted! Hey, you can even try an XP CMD line EDIT (filename)
to display it!
I would say the resistance A - B is therefore one third of 10 Ohm. 3.333' Ohm.
73 Dick VK3ABK
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