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VK3ABK > TECH     18.10.06 09:34l 38 Lines 1315 Bytes #999 (0) @ WW
BID : 41576_VK3HEG
Read: GUEST OE5EWL DL8FBH DL1LCA DH0GHU
Subj: Re: Congrats. Phys. DK2ZA.
Path: DB0FHN<DB0MRW<DK0WUE<SP7MGD<VK7AX<VK3HEG
Sent: 061018/0236Z @:VK3HEG.#WEV.VIC.AUS.OC #:41576 [Ballarat] $:41576_VK3HEG
From: VK3ABK@VK3HEG.#WEV.VIC.AUS.OC
To  : TECH@WW

Hello again,

Helmut, DK2ZA, Sent this network that asks for the resistance A - B.

                         ---------------------------------------
                         |                                     |
 A         |--------|    |    |--------|         |--------|    |    B
 o---------| 10 Ohm |---------| 10 Ohm |---------| 10 Ohm |---------o
      |    |--------|         |--------|    |    |--------|
      |                                     |
      ---------------------------------------


 Many people find it difficult to determine the resistance between A and B.
----------------------

Comment...But I see this network in a different way....

                     A                       B
                     ³          10           ³
                     ÃÄÄÄÄÄÄ/\/\/\/\/\ÄÄÄÄÄÄÄ´
                     ³          10           ³
                     ÃÄÄÄÄÄÄ/\/\/\/\/\ÄÄÄÄÄÄÄ´  
                     ³          10           ³
                     ÀÄÄÄÄÄÄ/\/\/\/\/\ÄÄÄÄÄÄÄÙ

I thought I would use my old diagram for Helmut's previous question. I don't
like to see it wasted!  Hey, you can even try an XP CMD line EDIT (filename)
to display it!

I would say the resistance A - B is therefore one third of 10 Ohm. 3.333' Ohm.

73 Dick VK3ABK



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