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ZL4AJS > TECH 27.09.05 15:01l 40 Lines 1352 Bytes #999 (0) @ WW
BID : F10289ZL4AJS
Read: GUEST DL1LCA OE7FMI
Subj: Re: calculations
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Sent: 050926/2029Z @:ZL4GQ.#95.NZL.OC #:35497 [Invercargill] FBB7.00i
From: ZL4AJS@ZL4GQ.#95.NZL.OC
To : TECH@WW
VK6BE wrote:-
> I calculated the height of a tower here when I was asked about it by
> measuring the base (measured from the base of the tower to a spot a
> convenient distance from the base) of the triangle and the angle to the
> top. Easy using Pythagoras.
I don't think you could have used Pythagoras for that example!
It is necessary to use the properties of trigonometric ratios, in this
case the tangent. The given measurements were one side (the base, or
adjacent side) and one angle. The measurement required is the height of
the tower (opposite side). The workings would be thus:
making a = adjacent side or distance from foot of tower
o = opposite side or height of tower
C = angle of elevation from observer's location to top of tower
tan(C) = o / a
=> o = a * tan (C)
Using this formula and a scientific calculator it is very easy to
accurately work out the tower's height. Pythagoras, however, could not be
used because for that you need to know two sides to work out the third.
73.
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:: Andrew ZL4AJS@ZL4GQ.#95.NZL.OC ::
:: High School student (homeschooled) 18 ::
:: Ohai, Southland, NZ ::
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Timed 07:58 on 27-Sep-2005
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