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VK6BE > TECHNI 25.09.05 21:36l 21 Lines 712 Bytes #999 (0) @ WW
BID : E90388VK6BE
Read: GUEST DL1LCA OE7FMI
Subj: Re: Re^2: calculations
Path: DB0FHN<DB0FOR<DB0SIF<DB0EA<DB0RES<ON0AR<VK6HGR<VK6BBR<VK6ZRT<VK6TJ<
VK6JY
Sent: 050924/1435Z @:VK6JY.#ALY.#WA.AUS.OC #:2689 [Albany] wFBB7 $:E90388VK6BE
From: VK6BE@VK6JY.#ALY.#WA.AUS.OC
To : TECHNI@WW
Pardon me Patrick but when I did matriculation maths only a rightangled
triangle had a hypotenuse. The hypotenuse is the side opposite the right
angle. Your other formula might be correct but it is not calculating a
hypotenuse. To do that it must be a right angle triangle. (you said
rectangular which is not correct either - a rectangle has four sides not
three).
Cheers,
Bob VK6BE.
>
> This is only valid in the special case of a rectangular triangle. On other triangles things get a
little bit more complex. The complete formula is :
>
> c^2 = a^2 + b^2 - 2 *a*b*cos(d)
>
> (a, b: shorter sides, c: longest side, d: angle between the shorter sides)
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