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DF3VI > TECHNIK 23.09.05 18:08l 21 Lines 594 Bytes #999 (30) @ WW
BID : N9FDB0II_01V
Read: GUEST DL1LCA OE7FMI
Subj: Re^2: calculations
Path: DB0FHN<DB0RGB<OK0PPL<DB0RES<DB0GOS<DB0OVN<DB0II
Sent: 050923/1604z @:DB0II.#NRW.DEU.EU [BCM M'Gladbach] obcm1.06b52 LT:030
From: DF3VI @ DB0II.#NRW.DEU.EU (Patrick)
To: TECHNIK @ WW
Reply-To: DF3VI @ DB0OVN.#NRW.DEU.EU
X-Info: Sent with login password
GM7HUD wrote:
> Vk5KMG wrote:
> >I want to work out the length of the hypotenuse of the triangle
>
> Pythagoras!
> h^2 = a^2 + b^2.
This is only valid in the special case of a rectangular triangle. On other
triangles things get a little bit more complex. The complete formula is :
c^2 = a^2 + b^2 - 2 *a*b*cos(d)
(a, b: shorter sides, c: longest side, d: angle between the shorter sides)
For d=90 deg. is cos(90)=0 and Phytagoras comes out.
73, Patrick
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