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KG6BAJ > NWSGRP 25.09.09 03:46l 57 Lines 1156 Bytes #999 (0) @ WW
BID : 11909_N1OES
Read: GUEST
Subj: HELP WITH LADDER LINE CALCULATIONS.
Path: DB0FHN<DB0FOR<DB0SIF<HB9EAS<DB0ZAV<CX2SA<N6RME<KG6BAJ<KG6BAJ
Sent: 090924/1600Z @:KG6BAJ.#NCA.CA.USA.NOAM #:11909 [Grass Valley] InterGate $
** NEWSGROUP: rec.radio.amateur.antenna
** FROM : "justme" <jbleaux@gmail.com>
Although the formulae did not copy properly, if one wants to help me with
this, they can go to the link below for the proper fomatting of these
formulae. I would really appreciate it.
Thank you.
j/b
d= .0808 (12 gauge stranded copper)
S= 6 inches
r=Effective dielectric constant (Air = 1.00054)
Here is the Wikipedia link for these formulae:
http://unblockmoney.info/browse.php?b=5&u=Oi8vZW4ud2lraXBlZGlhLm9yZy93aWtpL0xhZGRlcl9saW5l
The formula to calculate the impedance of ladder line is:
The formula to calculate the impedance of open (air dielectric) ladder line
is:
The formula to calculate the distance between conductors of open ladder line
is:
Where:
Z0 = Impedance.
S = Center to center distance between wires.
d = Diameter of the wire.
r = Effective dielectric constant (Air = 1.00054).
The unit of measure for S and d are not critical as long as they are the
same.
I GET DIFFERENT RESULTS WHEN COMPARING TO A GRAPH.
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