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W5DXP  > ANTENN   19.05.05 20:11l 58 Lines 2260 Bytes #999 (0) @ WW
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Subj: Re: zub zero//How do radio waves work?
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From: W5DXP@LU4EGV.BUR.BA.ARG.SA
To  : ANTENN@WW

From: w5dxp@hotmail.com
Date: Thu, 19 May 2005 07:25:59 -0500
Newsgroups: rec.radio.amateur.antenna
Distribution: ww
Subject: Re: zub zero//How do radio waves work?
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R:050519/1547Z @:LU4EGV.COM.AR HamServ V2.66
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Richard Clark wrote:
> On Thu, 19 May 2005 01:13:39 GMT, ml <m@di.net> wrote:

>>>Free electrons are free (pun intended) to emit photons of any
>>>frequency. Electrons that are not free are not free to emit photons
>>>of any frequency. Superposition of EM waves is what makes it possible
>>>for "the plethora of frequencies" to exist all at the same time in
>>>the same place.
>>
>>how can this be??
> 
> It can't ...

But it appears to be nonetheless. Quantum Physics is not logical
but makes extremely accurate predictions.

 From "QED", by Feynman: "So now, I present to you the three basic
actions, from which all the phenomena of light and electrons arise.
- Action #1: A photon goes from place to place.
- Action #2: An electron goes from place to place.
- Action #3: An electron emits or absorbs a photon."

Feynman describes the free electron in a lithium atom: "- the third
electron is farther away from the nucleus than the other two ... and
exchanges fewer photons (with the nucleus). This causes the electron
to easily break away from its own nucleus under the influence of
photons from other atoms." This "breaking away from its own nucleus"
describes the action and reaction of free electrons in metals such as
aluminum and copper.

A lithium atom has one free electron. That free electron is capable
of emitting or absorbing photons of any frequency including ham
frequencies. A helium atom has no free electrons and therefore can
emit only photons of frequencies associated with discrete orbits.
-- 
73, Cecil  http://www.qsl.net/w5dxp

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